## Hypergeometric Distribution

Consider a statistical experiment wherein a sample of *n* observations is to be taken from a population of size *N*. The population contains *k* items that are labeled ‘success’ and *N – k* items that are labeled ‘failure’. If a random variable X assumes the value equal to the number of successes in the sample of size *n*, then X has a ** hypergeometric distribution** with parameters

*N*,

*n*and

*k*. The random variable X is said to be hypergeometrically distributed with parameter

*N*,

*n*and

*k*, and has the following probability distribution:

**Mean (µ) of the Hypergeometric Distribution:**

µ = *nk/N*

**Variance (σ ^{2}**

**) of the Hypergeometric Distribution:**

σ^{2} = *[(n)(k)(N-n)(1-k/N)]/[N(N-1)]*

*Source:*

*De Silva, S., D’Andreti, P. (1997). ***Discrete Probability Distribution – HYPERGEOMETRIC DISTRIBUTION . Retrieved December 2, 2006 from http://library.thinkquest.org/10030/6dpdhd.htm.**

hi,

i have this example with me, but yet i have no idea how to do the calculation for the P(X) formula as mention above. please guide.